a cricketer can throw a ball to a maximum horizontal distance of 100 M with the same effort he throws the ball vertically upward the maximum height attained by the ball is
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Along horizontal
For maximum range θ = 45°
R = u²Sin(2θ) / g
R = u² Sin(2 × 45) / g
R = u² / g
100 = u² / g ………(1)
Along vertical
Maximum height = u² / (2g)
= 100 / 2 ………[∵ From (1)]
= 50 m
Maximum height attained by ball is 50 m
For maximum range θ = 45°
R = u²Sin(2θ) / g
R = u² Sin(2 × 45) / g
R = u² / g
100 = u² / g ………(1)
Along vertical
Maximum height = u² / (2g)
= 100 / 2 ………[∵ From (1)]
= 50 m
Maximum height attained by ball is 50 m
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