Question

a cricketer can throw a ball to a maximum horizontal distance of 100 m. how much high above the ground can the cricketer thriw the same ball ?

Answer 1

To throw a ball at maximum horizontal distance angle must be 45°.

So the maximum range is given by

S = V^2 / g

100 = V^2 / 10

1000 = V^2


$v = \sqrt{1000}$
Now maximum height is given by

h = V^2 /2g

h = 1000 / 2×10

h = 100/20 = 50m

So Maximum height to which ball goes will be 50m.


Thanks