Question

A cricketer can throw a ball to a maximum horizontal distance of 100m with the same speed how much high above the ground the cricketer through the same board

Answer 1

We know that horizontal range is maximum if the angle of projection is 45o and is given by

Rmax = u2 / g

Here, Rmax = 100 m

so, u2 / g  = 100 m

If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground

Hmax = u2 / 2g  = 100 /2 = 50 m.