Question

A cricketer can throw a ball upto a maximum horizontal height of 100 m . How much height above the ground he can throw the same ball.

Class 11

topic : Projectile Motion

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Answer 1

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Answer 2

[0010001111]... Hello User... [1001010101]
Here's your answer...

The formula for range of a projectile is...
$\frac{ {v}^{2} \sin2 \alpha }{g}$
The range of a projectile is maximum when the angle of projection is 45°.

Substituting the given values in the above equation, we get...

100 = (v² sin 90) ÷ 10
v² = 1000
Keeping the value this way...
Maximum height of a projectile is...
$\frac{ {v}^{2} { \sin \alpha }^{2} }{2g}$
Substituting the values we have...

H = (1000×1/2)÷20
= 500/20
= 25 m

This is the maximum height the projectile can achieve when its angle of projection is 45° and its range is 100 m.

Alternatively, you can remember that maximum range is achieved at 45° and at 45°, R = 4H.

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