Math, asked by syed5349, 1 year ago

A cricketer had a certain average of runs for his 64 innings. In his 65th innings he is bowled out for no score on his part. This brings down his average by 2 runs. His new average of runs is

Answers

Answered by shivamdalmia
16
Let his earlier average be A, and let his total runs in all innings be T

Number of innings he played earlier = 64
Average = Total no of runs in all innings / No. of innings
A = T/64
or T = 64A....(1)
Now, after playing his 65th innings, we have

A - 2 = T/65
or 65A - 130 = T....(2)
Putting (1) in (2), we get
65A - 130 = 64A
65A - 64A = 130
A = 130
His old average = 130 runs
His new average = 130 + 2 = 132 runs.
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