Math, asked by lokeshnain4530, 1 year ago

A cricketer has a certain average for 10 innings. In the eleventh innings, he scored 108 runs, thereby increasing his average by 6 runs. His new average is

Answers

Answered by BrainlyVirat
10

Answer: 48

Step by step explanation:

Let the average be x.

Sum of scores in 10 innings = 10x.

In the 11th inning, he scored 108 runs.

.°. Avg = (10x + 108)/11

Given that, Avg increased by 6,

x + 6 = (10x + 108)/11

11x + 66 = 10x + 108

x = 108 - 66

x = 42

Thus, his new average = x + 6

= 42 + 6

= 48

His new average is 48

Answered by Anonymous
4

Refer the attachment.

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