Question

A cricketer has a mean score of 45 in 8 innings . How many runs are to be scored in the 9th innings to raise the mean score to50

Answer 1

Answer:

let upto 8 inning the total score be X

SO,           X/8 =45

               X= 45*8= 360

LET HE SHOULD SCORE Y

SO, NOW TOTAL RUNS= 360+Y

SO MEAN= (360+Y ) /9

BUT MEAN =50

SO,       50=(360+Y)/9

            Y=90(ANS)

Step-by-step explanation:

Answer 2

90 runs are to be scored in the 9th innings to raise the mean score to50

Step-by-step explanation:

A cricketer has a mean score of 45 in 8 innings .

$45 = \frac{\text{Sum of all scors in 8 innings}}{8}$

$45 \times 8 = \text{Sum of scores of 8 innings}\\360= \text{Sum of scores of 8 innings}$

Let the score of 9 inning be x

So, Sum of scores of 9 innings = 360+x

We are supposed to find How many runs are to be scored in the 9th innings to raise the mean score to50

So, $50=\frac{360+x}{9}\\450=360+x\\450-360=x\\90=x$

Hence 90 runs are to be scored in the 9th innings to raise the mean score to50

#Learn more:

A cricketer has a mean score of 45 in 8 innings . How many runs are to be scored in the 9th innings to raise the mean score to50

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