Question

A cricketer has played in 45 innings and his average score is 50. Out of these 45 innings he did not score more than 50 in exactly 30 innings. What is
the highest possible value of the average score in these 30 innings?

Answer 1

Step-by-step explanation:

Let the lowest score in one innings be x. Then,

Highest score in an innings = x + 172

Total runs in 40 innings = 40 x 50 = 2000

Total runs in 38 innings = 38 x 48 = 1824

Given, 2000 - {x + (x + 172)} = 1824

⇒ 1828 - 2x = 1824 ⇒ 2x = 4 ⇒ x = 2

∴ Highest score = 172 + 2 = 174

Answer 2

Answer:

Step-by-step explanation:70 students, if the average mark of 40 students is 75, what is the average mark of the ... Hence the average of the remaining 30 students = 2600/30 = 86.66 ... Let's look at one more sum similar to the one discussed above. ... Again, if the batsmen had scored 45 in his latest inning his average would remain in tact  75