A cricketer hit a ball with a velocity of 20m/s and the ball reaches to the boundary after 5s. Determine how far was the boundary from the cricketer.
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cricketer hits a ball with a velocity 25 m/s at 60^0 above the horizontal. How far above the ground it passes over a fielder 50 m from the bat (assume ...
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100 m
Explanation:
Given data
velocity of the ball= 20m/s
time taken to reach the boundary= 5s
then by the formula of distance. d=v*t where d is distance v is velocity and t is time.
d=v*t
d=20*5
therefore d=100m
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