Math, asked by nandas8, 1 year ago

A cricketer hits 120 runs in 150 balls during a test match 20% of the runs came in 6s 30% in 4 s 25% in 2s and the rest in1s how many runs did he score

Answers

Answered by Nikhilv
93
Total runs hit by the cricketer = 120 runs

Now 20% of the runs came in sixes.
So, Total runs came in sixes = 120×20/100 = 24 runs
30% of the runs came in fours.
So, Total runs came in fours = 120×30/100 = 36runs
25% of the runs came in 2's.
So, Total runs came in 2's = 120×25/100 = 30runs
And total runs came in singles = Total runs scored - (Total runs came in sixes + Total runs came in fours + Total runs came in 2's)
= 120 - (24 + 36 + 30)
= 120 - 90
= 30 runs
Therefore, total runs came in singles = 30 runs
Percentage of shots scoring ones = Runs came in singles×100total runs scored = 30×100/120 = 25%
Answered by dharitriprusty57
12

Answer:

total runs hit by the cricketer=120

Now 20%of the runs came in sixes

℅of runs in sixes =20/100 ×120 =24runs

30 % of the runs came in fours

℅of runs in fours=30/100×120 =36runs

25%of the runs came in twos

%of runs in twos

=25/100×120=30run

The total runs came in single=

120-(24+36+30)

120-90

30 runs

30%of the runs came in ones/single

%of runs in ones/single

=30/120×100=25 %

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