Math, asked by abc72, 1 year ago

a cricketer scored a total 62runs in 96 balls. He hits 3sixes, 8 fours, 2 twos and 8 singles what percentage of the total runs came in (1) sixes (2) fours (3) twos (4) singles

Answers

Answered by Maque
83
Runs scored in 4s = 8 x 4 = 32
Percentage of runs scored in 4s = 32/62 x 100 = 51.62 % (approx.)
Runs scored in 6s = 3 x 6 = 18
Percentage of runs scored in 6s = 18/62 x 100 = 29.03 % (approx.)
Answered by BrainlyRacer
90

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\bold{(i)\:Sixes}\\\\\implies Total\:runs\:come\:in\:sixes=6\times3=18\:runs\\\\Percentage\:of\:runs\:came\:in\:sixe's\\\\=\huge{\frac{Total\:run\:come\:in\:sixes\:\times100}{Total\:runs\:scored}}\\\\=\frac{18\times100}{62}\\\\=29.03\%\\\\\\\bold{(ii)\:Four's}\\\\\implies Total\:runs\:come\:in\:fours=8\times4=32\:runs\\\\\implies Percentage\;of\:runs\:come\:in\:fours\\\\=\huge{\frac{Total\:runs\:come\:in\:fours}{Total\:runs\:scored}}\\\\=\frac{32\times100}{62}=51.61\%\\\\\\

\bold{(iii)\:Two's}\\\\\implies Total\:runs\:come\:in\:twos=2\times2=4\:runs\\\\\implies Percentage\:of\:runs\:come\:in\:twos\\\\=\huge{\frac{Total\:runs\:come\:in\:twos\times100}{Total\:runs\:scored}}\\\\=\frac{4\times100}{62}=6.45\%\\\\\\\bold{(iv)\:Single's}\\\\\implies Total\:runs\:come\:in\:singles=1\times8=8\:runs\\\\\implies Percentage\:of\:runs\:come\:in\:singles\\\\=\huge{\frac{Total\:runs\:come\:in\:singles\times100}{Total\:runs\:scored}}\\\\=\frac{8\times100}{62}=12.90\%

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