Question

A cricketer scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100.
Find the mean and median of the above data.

Answer 1

Answer:

Mean = 50

Median = 45.5

Step-by-step explanation:

Mean = 0+35+40+45+46+58+76+100/8

= 50

Median = 45+46/2

= 91/2

= 45.5

Answer 2

★ How to do :-

Here, we are given with the scores of a cricketer in his eight innings. We are asked to find the mean and median score of the given data. So, to find the mean score first we should add all the given data and then we should divide it with the number eight. The formula of mean is to add all the observations and then we should divide it with the total number of observations. Next, to find the median score, first we should arrange the observations in ascending or descending order and then we should find the middle value.

$\:$

➤ Solution :-

Mean :-

${\tt \leadsto \dfrac{58 + 76 + 40 + 35 + 46 + 45 + 0 + 100}{2}}$

${\tt \leadsto \dfrac{209 + 191}{2} = \dfrac{400}{2}}$

${\tt \leadsto \cancel \dfrac{400}{2} = \boxed{\tt 200}}$

$\:$

Median :-

${\tt \leadsto 58, 76, 40, 35, 46, 45, 0, 100}$

Ascending order :-

$\tt \leadsto 0, 35, 40, 45, 46, 58, 76, 100$

$\tt \leadsto \cancel{0}, \cancel{35}, \cancel{40}, 45, 46, \cancel{58}, \cancel{76}, \cancel{100}$

Here, we are obtained with two numbers, so we should find the mean of those two numbers.

${\tt \leadsto \dfrac{45 + 46}{2} = \dfrac{91}{2}}$

${\tt \leadsto \cancel \dfrac{91}{2} = \boxed{\tt 45.5}}$

$\Huge\therefore$ The mean score is 200 and the median score is 45.5.

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More to know :-

• Mean is also known as Arthemetic mean or it's also called as average. It is calculated by the following formula :-

${\longrightarrow \sf \dfrac{Sum \: of \: all \: observations}{Number \: of \: observations}}$

• Median is calculated by arranging the observations in ascending or descending order and then we should find the middle value. If there are two numbers obtained, then we should find the mean of those two numbers. There is no specific formula for median.