Question

a cricketer throws a ball at an angle of 30 degree with a velocity of 20 metre per second find its time of flight​

Answer 1

Answer:

It will follow parabolic path

Range is given as,

R=

g

u

2

sin2θ

R=

9.8

14

2

×sin60

R=17.32m

Time taken to reach the ground in next part

=

g

2H

=

9.8

2×12

=1.56sec

Distance traveled in next part

S=ut

S=14×1.56

S=21.84m

Total distance=21.84+17.32=39.16m

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Answer 2

Step-by-step explanation:

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