Question

.A cricketer throws a ball at an angle of 30° with the horizontal having velocity 30ms⁻¹. The maximum height attained by the ball is(Take g = 10 ms⁻²) *
(a) 40 .25m
(b) 20 .50m
(c) 11.25 m
(d) 50 m​

Answer 1

The right answer is option ( c ) ☺️☺️☺️☺️

Answer 2

Answer:

(c) The maximum height attained by the ball is 11.25 m.

Explanation:

The ball will follow the projectile motion when it is thrown at an angle with horizontal.

Given,

A cricket ball is thrown at an angle,θ = 30°

The initial velocity, u = 30ms⁻¹

The maximum height(H) reached,

$H = \frac{u^2sin^2\theta}{2g} \\\\H = \frac{(30)^2\times (\frac{1}{2})^2 }{2\times 10} \\\\H = \frac{900}{2\times 10\times 4}\\\\ H = 11.25\ m$

Hence, the maximum height attained by the ball is 11.25 m.

Projectile motion is the motion of an object that is thrown, shot, or otherwise projected into the air, and is subject only to the force of gravity and air resistance (if present). It can be described mathematically by the equations of motion and can be used to determine the maximum height, range, time of flight, and other properties of the motion.

To learn more about projectile motion, click on the link below:

https://brainly.in/question/208506

To learn more about maximum height, click on the link below:

https://brainly.in/question/49564502

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