Question

A cricketer throws a ball towards the wickets at a distance of 7.5m from him by making an angle of 30°. Find the velocity of thrown?​

Answer 1

Explanation:

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I am not sure of answer but it can work

so here we go

so here ac represents velocity of ball thrown by fielder towards wickets

also bc is distance between wickets and fielder which is 7.5 m

and angle c is angle made by fielder while throwing ball

therefore angle c=30

as it is a ryt angle triangle

we can apply concept of trigonometry

so then cos c=bc upon ac

ie cos 30=7.5/ac

so cos 30=root 3/2

so then ac=15/root 3

apply conjugate method ie multiply rhsthroughout by root 3 we get

ac=15×root 3/3

ie ac=15 root 3

so ac=15×1.73

thus ac=25.95 m/s

hence velocity of ball thrown is 25.95 m/s