Question

a criket ball of mass 0.32 kg moving with a speed of 40 m/s is brought to rest in 0.2 sec. What is the average force applied by the player? [ Ans. 64N ]​

Answer 1

Momentum:

• it defines the amount of force applies for a interval of time.
• force is responsible for changing the Momentum of an object.

$\implies\bf Force = \dfrac{dP}{dt}$

Solution:

$\implies\rm F = \dfrac{final\: momentum - initial \: momentum}{time \: taken}$

$\implies\rm F = \dfrac{ P_f - P_i}{dt}$

$\implies\rm F = \dfrac{ mv_f - mv_i}{t}$

$\implies\rm F = \dfrac{m(v_f - v_i)}{t}$

$\implies\rm F = \dfrac{0.32(0-40)}{0.2}$

$\implies\rm F = \dfrac{-(0.32\times 40)}{0.2}$

$\implies\rm F = \dfrac{‐ 32\times 40\times 10}{100\times 2}$

$\implies\rm F = \dfrac{- 32\times 4}{2}$

$\implies\rm F = - 32\times 2$

$\implies\bf F = 64\: N\: \hat{-i}$

-- negative implies the opposite impact of force with respect to motion.

★ 64 N of average force is applied by the player.