a criketar can throw a ball to a maximum horizontal distance of 100m how much high above the ground can the criketar throw the same ball
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Answer:
25m
Explanation:
For range to be maximum, theta =45 degrees
R=u^2 sin(2×45)/g
R=u^2/g
Height (h)= u^2sin^2(45)/2g
h= u^2/4g
Therefore h=R/4
h=100/4=25m
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