a crime suspect passes an intersection in a car travelling at 110 mi/hr. the police pass the intersection 3.0 min later in a car traveling at 135 mi/hr. how long is it before the police overtake the suspect?
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Relative speed of the police car with respect to criminal's car:
135 - 110 = 25 mi/hr = 5/12 mile/minute
we can treat as if criminal car is stationary and police car is going at above speed.
Distance of criminal's car from junction when police car is at junction:
3 min * 110 miles / 60min = 5.5 miles
time to cover this distance = 5.5 / (5/12) = 13.2 minutes
135 - 110 = 25 mi/hr = 5/12 mile/minute
we can treat as if criminal car is stationary and police car is going at above speed.
Distance of criminal's car from junction when police car is at junction:
3 min * 110 miles / 60min = 5.5 miles
time to cover this distance = 5.5 / (5/12) = 13.2 minutes
kvnmurty:
thanks and welcome
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Answer:
Step-by-step explanation:
Relative speed of the police car with respect to criminal's car:
135 - 110 = 25 mi/hr = 5/12 mile/minute
we can treat as if criminal car is stationary and police car is going at above speed.
Distance of criminal's car from junction when police car is at junction:
3 min * 110 miles / 60min = 5.5 miles
time to cover this distance = 5.5 / (5/12) = 13.2 minutes
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