A cross is made between different homozygous pea plants for contrasting flower positions. A)find out the position of flowers in f1 generation on the basis of the genotypes. B)work out the process up to f2 generation. C)compute the relative fraction of various genotypes in the f2 generation.
Answers
Answer:
in f1 generation all plants are at constricted and in f2 all are controcted but few are flated also
A cross is made between different homozygous pea plants for contrasting flower positions.
A) The position of flowers in f1 generation on the basis of the genotypes:
Parents: Dominant – Axial flower (AA) and Recessive – Terminal flower (aa)
When we cross both the parent the F1 generation will result in Aa, Aa, Aa, and Aa. It shows that the position of flowers in F1 generation is Axial as all the offspring has A in them.
B) The process up to f2 generation:
When we cross the f1 generation with any one of the parent, we get the f2 generation in the following way:
AA X aa
Aa Aa Aa Aa
It also shows that all the offspring are in axial position.