Question

A cross was made between pure breeding pea plants one with round and green seeds and the seeds and the other with wrinkled and yellow seeds.

a) Write the phenotype of F1 progeny. Give reason for your answer.

b) Write the different types of F2 progeny obtained along with their ratio, when F1 progeny was self-crossed.​

Answer 1

$\huge\red{Hey Mate}$

The resulting cross will be dihybrid cross since two traits are involved .

a) The phenotype of F1 progeny is : Round and Green seeds .

b) The different types of F2 progeny obtained are -

RRGG, RRGg, RrGG, RrGg, RRGg,RRgg,RrGg,Rrgg,RrGG,rrGG,rrGg,RrGg,Rrgg,rrGg,rrgg

So the phenotypic ratio is :

Round green : Round yellow: wrinkled green: wrinkled yellow

=

9:3:3:1

Refer to the attachment ...