a crossection of a ruler which is a rectangle of 2.5 cm by 0.2 cm on which is surmounted an isosceles trapezium[one in which the non parallel sides are of equal length]. The shorter of the parallel sides of a trapezium is 0.7 cm long if the greatest height of the ruler is 0.4 cm and it is 33 cm long ,calculate its surface area
Answers
Answered by
1
Answer:
Area =12(sum of parallel sides)× distance between them
12(7x+4x)×2x=176
11x2=176⇒x216
⇒x=4
AB=7×4=28cm
CD=4×4=16cm
CM=2×4=8cm
AM=AN+NM
⇒AN+16
⇒6+16=22
(AN=BM=122=6)
AC2=CM2+AM2
AC2=82+222
Step-by-step explanation:
plzzzz mark broo
Similar questions