Question

a crossection of a ruler which is a rectangle of 2.5 cm by 0.2 cm on which is surmounted an isosceles trapezium[one in which the non parallel sides are of equal length]. The shorter of the parallel sides of a trapezium is 0.7 cm long if the greatest height of the ruler is 0.4 cm and it is 33 cm long ,calculate its surface area

Answer 1

Answer:

Area =12(sum of parallel sides)× distance between them

12(7x+4x)×2x=176

11x2=176⇒x216

⇒x=4

AB=7×4=28cm

CD=4×4=16cm

CM=2×4=8cm

AM=AN+NM

⇒AN+16

⇒6+16=22

(AN=BM=122=6)

AC2=CM2+AM2

AC2=82+222

Step-by-step explanation:

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