a crow bar of lenght 2.0 m is used as a machine to liftba box of 100 kgf by placing a fulcrum at a distance of 0.1 m from the box . calculate the effort required. answer should be (5.26 kgf) Hint : Effort arm - 2.0m - 0.1m - 1.9 m
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Length of crow bar = 2m
length of load arm = 0.1M
length effort arm = length of crow bar -length of load arm
=2−0.1=1.9m
so, velocity ratio = length of effort arm/length of load arm = 1.9/0.1 = 19
use formula, velocity ratio = load/effort
19 = 100kgf/effort
effort = 100/19= 5.26 kgf
hence,5.26 effort is required.
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