Question

a crowbar having the length of 1.75m is used to balance a load of 500N.if the distance between the fulcrum and the load is 0.5m what is the effort applied to balance the load.

Answer 1

L=load LA=load arm

E= effort EA= effort arm

Answer 2

The effort applied to balance the load : 200 N

Explanation:

Equilibrium rotation

∑$T$ = 0

F₁ . d₁-F₂ . d₂=0

F₁ . d₁=F₂ . d₂

F₁=500 N

d₁=0.5 m

d₂=1.75 - 0.5 = 1.25 m

500 * 0.5 = F₂ * 1.25

F₂ = 500 * 0.5 / 1.25

F₂ = 200N

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