Question

A crowbar of length 100cm used to lift a load of 50N. The fulcrum is ar a distance of 20cm from the load.

Answer 1

Answer:

Given: L = 5 kgf, Load arm = 20 cm, Effort arm = 100 – 20 = 80 cm.

(Since the crow bar is the lever of first order with fulcrum in between the load and the effort).

(i) Mechanical advantage = Effort arm/Load arm = 80/20 = 4

(ii) M.A. = Load(L)/Effort(E)

∴ Effort = Load(L)/M.A. = 5/4

= 1.25 kgf.

Explanation:

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Answer 2

Answer:

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Explanation:

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