a crystalline solid forming cubic lattice is made of two elements A and B atoms of A are present at corner and atom of B at face centres of all along one of the body diagonal are missing then the simplest formula of the solid is
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Number of atoms of X in fcc packing (at corners and face centres of cubic unit cell) =8×
8
1
+6×
2
1
=4
Number of atoms of Y at octahedral voids =4
Along one body diagonal there are two X atoms and one Y atom.
Number of effective atoms of X after removal
=4−2×
8
1
=
4
15
Number of effective atoms of Y after removal =4−1=3
X:Y=
4
15
:3
=5:4
∴ Simplest formula =X
5
Y
4
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