Question

A CSA of right circular cylinder of height 14 cm is 88cm square. find the diameter of the base of the cylinder

Answer 1

Height (h) of cylinder = 14cm
Let the diameter of cylinder be d.
Curved Surface Area of Cylinder = 88cm square
2πrh = 88 cm square
π dh = 88 cm square. (d = 2r)
22/7 × d × 14 = 88 cm
d = 2 cm
Therefore,the diameter of the base of the cylinder is 2 cm

Answer 2

Answer:

The diameter of the base of the cylinder is 2cm.

Step-by-step explanation:

Given:

Height of cylinder (h)=14 cm

Curved Surface Area of cylinder$=88 cm^{2}$

Let the diameter of the cylinder be d,

Curved Surface Area $= 2\pi rh$

Where r is the radius of the base of the cylinder

$2\pi rh =88 cm^{2}$

$2\cdot(\frac{22}{7})\cdot r\cdot14 = 88 cm^{2}$

$2r = 2cm$

$r=\frac{2}{2} cm$

$r=1cm$

We know, $d={r} \cdot {2}$

So, $d=2cm$

Therefore, the diameter of the base of the cylinder is 2 cm.