Question

A
cthree bundled of shin
308 m and 490 m longosting
that the bandles can be cut up
in to
left over et
392m
without ang​

Answer 1

Greatest length of the string that is to be cut from the bundle can be found by taking H.C.F of all the three bundle lengths

Three lengths are 392m, 308m, 490m

Factors of 392 = 2x2x2x7x7

Factors of 308 = 2x2x7x11

Factors of 490 = 2x5x7x7

Common factors of the three are: 2 and 7

Therefore, H.C.F = 2x7 = 14

So, the strings in each bundle can be cut into 14m so that no string is 14m so that no string is left out.