Question

A Cu wire of length 2m and area of cross
section 2mm.and elongated by 1mn. Calcu-
late the density. ​

Answer 1

Answer:

W=6×10  

−4

J

Explanation:

ANSWER

W=  

2

1

​  

×stress × volume

stress=y×strain

W=  

2

1

​  

(strain)  

2

×Vol

Strain =  

L

ΔL

​  

=(  

2

10−4

​  

)

vol=A×L=2×10  

−6

×2

=4×10  

−6

 

W=  

2

1.2×10  

11

 

​  

×  

4

10  

−8

 

​  

×4×10  

−6

 

=0.6×10  

−3

 

W=6×10  

−4

J