Question

A cube-1 by a cube-2a+2 by a

Answer 1

Hi ,

a³ - 1/a³ - 2a + 2/a

= ( a³ - 1/a³ ) - 2( a - 1/a )

= ( a - 1/a ) [ a² + 1 + 1/a² ] - 2( a - 1/a )

= ( a - 1/a ) [ a² + 1/a² + 1 - 2 ]

= ( a - 1/a ) [ ( a² + 1/a² - 1 )



Or

( a³ - 1/a³ ) - 2( a - 1/a )

= ( a - 1/a )³ + 3( a - 1/a ) - 2( a - 1/a )

= ( a - 1/ a )³ + ( a - 1/a )

= ( a - 1/a )[ ( a - 1/a )² + 1 ]

I hope this helps you.

: )

= ( a - 1/a ) [ a² + 1/a² -2 + 1 ]

= ( a - 1/a ) ( a² + 1/a² - 1 )