Question

a cube b cube - 1÷a cube b cube 1÷a cube 1 ÷b cube​

Answer 1

Answer:

a³ - b³ + 1 +3ab

= a³ + ( - b )³ + 1³ - 3 × a × ( - b ) × 1

= [ a+(-b)+1 ][a²+(-b)²+1²-a(-b)-(-b)1-1×a]

= ( a - b + 1 ) ( a² + b² + 1 + ab + b - a )