Question

a cube +b cube +c cube when a+b+c=0and abc=25

Answer 1

Answer:

a³+b³+c³=75

OR

a³+b³+c³=3(abc)

Step-by-step explanation:

a³+b³+c³

(a+b+c)³=a³+b³+c³+3(a+b)(b+c)(a+c)

=a³+b³+c³+3[(ab+ac+b²+bc)(a+c)]

=a³+b³+c³+3[a²b+a²c+ab²+abc+abc+ac²+b²c+bc²]

=a³+b³+c³+3a²b+3ab²+3ac²+3a²c+3bc²+3b²c+6abc

0=a³+b³+c³+6(25)+3a²b+3ab²+3ac²+3a²c+3bc²+3b²c

0=a³+b³+c³+150+3ab(a+b)+3bc(b+c)+3ac(a+c)

0=a³+b³+c³+150+3ab(-c)+3bc(-a)+3ac(-b)

0=a³+b³+c³+150-9abc

0=a³+b³+c³+6(25)-9(25)

0=a³+b³+c³-3(25)

0=a³+b³+c³-75

a³+b³+c³=75

OR

a³+b³+c³=3(abc)

• HOPE YOU GOT IT
• IF YES MARK MY ANSWER AS THE BRAINLIEST ANSWER
• AND GIVE ME A BIG HEART

Answer 2

If a+b+c = 0 then
a cube + b cube + c cube = 3 abc
So ans is 3 * 25 = 75
You can see pic
Mark as brainliest