Question

A cube is placed inside a cone of radius 20 cm and height 10 cm, one of its faces being on the base of the cone and vertices of opposite face touching the cone. What is the length (in cm) of side of the cube?
Options
A 5, B 6, C 8, D 9 (in cms) ​

Answer 1

Step-by-step explanation:

Given A cube is placed inside a cone of radius 20 cm and height 10 cm, one of its faces being on the base of the cone and vertices of opposite  face touching the cone. What is the length (in cm) of side of the cube?

• Given a cube is placed inside the cone of radius 20 cm. Let the height pq of the cube inside the cone be p m = 10 m and let poq be the total height where o is the centre of pq.  
• Let oq = x and so oa be the side = x / 2
• Now po = 10 – x
• Also the base qb = 20 cm which is the radius.
• Triangle poa is congruent to pqb
• Po / pq = oa / qb
• 10 – x / 10 = x/2 / 20
• 10 – x / 10 = x / 40
• 400 – 40 x = 10 x
• 50 x = 400
• Or x = 400 / 50
• Or x = 8 cm

Reference link will be

https://brainly.in/question/15911456