Question

A cube minus b cube minus b cube - 3abc ka formulas

Answer 1

Answer:

a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac)

If a+b+c=0

Then, a3+b3+c3=3abc

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Answer 2

answer:

$a ^{3} + b ^{3} + c ^{3} + (3abc) = (a + b + c)(a ^{2} + b ^{2} + c ^{2} - ab - bc - ca)$

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