A cube of 1m edge length is crushed in order to get small cubes of edge length 1mm. by which factor does the surface area increase
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Answer:
Explanation:
1m = 1000 mm
The volume of cube with 1000mm edge
V = 1000 × 1000 × 1000 mm°3
Let the number of cubes formed after crushing the original cube be n. The volume of total cubes thus formed will be
V1 = n(1 × 1 ×1) mm^3
Mathematically V= V1
n = 10^9
The surface area of the original cube
S = 6(1000 ×1000) mm^2
Where as that of the cubes formed after crushing the original cube
S1 = 6 × 10^9 (1×1)
Therefore factor of increase
F = 6×10^9/6×10^6 = 1000
F = 1000
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