Question

A cube of 4 cm has been painted on its surfaces in such a way that two opposite surfaces have been painted blue and two adjacent surfaces have been painted red. Two remaining surfaces have been left unpainted. Now the cube is cut into smaller cubes of side 1 cm each.

Answer 1

Step-by-step explanation:

Given  A cube of 4 cm has been painted on its surfaces in such a way that two opposite surfaces have been painted blue and two adjacent surfaces have been painted red. Two remaining surfaces have been left unpainted. Now the cube is cut into smaller cubes of side 1 cm each.

• We have a cube of 4 cm which is painted, like two opposite surfaces are blue and the two adjacent sides are red and the two remaining surfaces are not painted. Also the cubes are cut in such a way that the side of cube is 1 cm each. So we get  
• So a = side of the big cube / side of small cube.
•        = 4 / 1
•       = 4
• So the number of cubes with at least blue colour on its surface will be the number of cubes present at the blue surface.
•                                                                       = 2 x a^2
•                                                                      = 2 x 4^2
•                                                                      = 2 x 16
•                                                                      = 32

Reference link will be

https://brainly.in/question/16967032