Question

a cube of 9 cm edge is immersed completely in a rectangular vessel containing water if the dimensions of the base is 15cm and 12cm find the rise in water level​

Answer 1

Answer:

HELLO MATE ❣️

Step-by-step explanation:

Here a cube is immersed into a rectangular vessel which will result in cuboidal form when there will be rise in water level........

So, volume of cube = volume of cuboid

let rise of water level is H cm.

9^3= 15*12*H

H= (15*12)/(9*9*9)

H= about 0.2 cm

HOPE YOU ARE SATISFIED ❣️

Answer 2

Answer :

➥ The rase in water lavel = 4.05

Given :

➤ Edge of cube = 9 cm

➤ Base of rectangle vessel = 15 cm and 12 cm

To Find :

➤ The rase in water lavel = ?

Solution :

Volume of cube

$\tt{: \implies {s}^{3} = {9}^{3} }$

$\tt{: \implies 9 \times 9 \times 9}$

$\bf{: \implies \underline{ \: \: \underline{ \green{ \: \: 729 \: {cm}^{3} }} \: \: }}$

Area of base

$\tt{: \implies l \times b}$

$\tt{: \implies 15 \times 12}$

$\bf{: \implies \underline{ \: \: \underline{ \green{ \: \: 180 \: {cm}^{2} }} \: \: }}$

Now ,

Rise in water lavel

$\tt{: \implies \dfrac{Volume \: of \: cube}{Area \: of \: base \: of\:rectangle \: vessel} }$

$\tt{: \implies \cancel{\dfrac{729}{180} }}$

$\bf{: \implies \underline{ \: \: \underline{ \purple{ \: \: 4.05 \: \: }} \: \: }}$

Hence, the rase in water lavel is 4.05.