A cube of 9 cm egde is immersed completely in a rectangular vessel containing water. If the dimensions of the base are 15 cm and 12 cm, find the rise in water level in the vessel.
Answers
Given : Edge of cube = 9 cm
Length of base of rectangular vessel , l = 15 cm
Breadth of base of rectangular vessel , b = 12 cm
Volume of cube ,V = edge³
V = 9 × 9 × 9
V = 729 cm³
Area of base of vessel = l × b = 15×12 = 180 cm²
So, rise of water in vessel , h = Volume of cube/ area of base
h = 729/180
h = 4.05 cm
Hence, the rise in water level in the vessel is 4.05 cm.
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Given :
- Edge of cube = 9 cm
- Length of base of rectangular vessel = 15 cm
- Breadth of base of rectangular vessel = 12 cm
Formula used:Volume of cube ,V = edge³
Solutions:
V = 9 × 9 × 9
V = 729 cm³
Area of base of vessel = l × b = 15×12 = 180 cm²
h = Volume of cube/ area of base
h = 729/180
h = 4.05 cm