Question

a cube of 9cm edge is immersed completely in a rectangular vessel containing water. If the dimention of of the base are 15cm and 12cm find the rise in water level in the vessel​

Answer 1

Answer:

Step-by-step explanation:

The rise in water level in the vessel is 4.05 cm

Step-by-step explanation:

Given: edge of cube = 9 cm

dimensions of rectangular vessels is length: l = 15cm breadth; b= 12cm and height; h = h cm

Now he cube is immersed completely in the rectangular vessel

Now as we know

volume of cube = volume of liquid displaced( volume of cuboid)

Hence, the rise in water level in the vessel is 4.05 cm

Answer 2

Answer:

Step-by-step explanation:

Answer:  The rise in water level in the vessel is 4.05 cm

Step-by-step explanation:

Given: edge of cube = 9 cm

dimensions of rectangular vessels is length: l = 15cm breadth; b= 12cm and height; h = h cm

Now he cube is immersed completely in the rectangular vessel

Now as we know

volume of cube = volume of liquid displaced( volume of cuboid)

Hence, the rise in water level in the vessel is 4.05 cm

we know that vol. of the water displaced=vol. of the object immersed

here,  vol. of the obj.=9³=729

given,the base of the vessel=15cm*12m

so,the vol. of the displaced water=15*1200*h(converting m into cm)

729=18000h so, h=0.0405cm

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