a cube of 9cm edge is immersed completely into a rectangular vessel containing water. is the dimension of the base are 15cm and 12cm. find the rise in water level in the vessel.
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Given that: Edge of cube = 9 cm
And base of the rectangular vessel = 15 cm by 12 cm.
By immersing the cube in the rectangular vessel containing water, level of water rises.
Let the level of water rises by h cm
Using the Archimedes Principle, we have
Volume of replaced water = Volume of the cube
15*12*h = 9*9*9
h = 9*9*9/15*12
h = 4.05 cm
Hence, level of water rises by 4.05 cm.
hope this helps....
And base of the rectangular vessel = 15 cm by 12 cm.
By immersing the cube in the rectangular vessel containing water, level of water rises.
Let the level of water rises by h cm
Using the Archimedes Principle, we have
Volume of replaced water = Volume of the cube
15*12*h = 9*9*9
h = 9*9*9/15*12
h = 4.05 cm
Hence, level of water rises by 4.05 cm.
hope this helps....
Answered by
6
Given that: Edge of cube = 9 cm
And base of the rectangular vessel = 15 cm by 12 cm.
By immersing the cube in the rectangular vessel containing water, level of water rises.
Let the level of water rises by h cm
Using the Archimedes Principle, we have
Volume of replaced water = Volume of the cube
15*12*h = 9*9*9
h = 9*9*9/15*12
h = 4.05 cm
Hence, level of water rises by 4.05 cm.
And base of the rectangular vessel = 15 cm by 12 cm.
By immersing the cube in the rectangular vessel containing water, level of water rises.
Let the level of water rises by h cm
Using the Archimedes Principle, we have
Volume of replaced water = Volume of the cube
15*12*h = 9*9*9
h = 9*9*9/15*12
h = 4.05 cm
Hence, level of water rises by 4.05 cm.
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