A cube of each side 10 cm is placed inside a liquid. Calculate the thrust exerted by the liquid on any face, if the pressure at the face of the cube is 5Pa.
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Answer:
500
Explanation:
thrust is the perpendicular force ...so,
pressure= perpendicular force / area
= area = area of one side of cube = side^2 = 10^2
area = 100 cm^2
P= F/A
5= F/ 100
now cross multiply
5*100= F
500 N = F
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hey mate, it's ur answer....hope it will help you
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