Math, asked by royanamika1972, 8 months ago

a cube of edge 11cm is immersed completely in a rectangular vessel containing water.If the dimensions of the base of the vessel are 15cm*12cm find the rise in water level correct to 2 decimal places assuming no water flows.​

Answers

Answered by milinchinnadura
4

Answer:

7.39 cm

Step-by-step explanation:

Given, edge of the cube = 11 cm

Dimension of the base of the rectangular vessel = 15 cm × 12 cm

Let the rise in water level in the rectangular vessel be h cm.

Since, the cube is completely un messed in the rectangular vessel,

∴ Volume of water displaced in the rectangular vessel = Volume of the cube

⇒ 15 cm × 12 cm × h = (11 cm)3

⇒ h ≈ 7.39 cm

Thus, the rise in water level in the rectangular vessel is 7.39 cm approximately.

Answered by RvChaudharY50
0

Given :- A cube of 11 cm edge is immersed completely in a rectangular vessel containing water . if the dimension of the base of the vessel are 15*12cm find the rise in water level to 1 decimal place assuming no water overflows ?

Solution :-

we have,

→ Edge of cube = 11 cm.

so,

→ volume of cube = (Edge)³ = (11)³ = 1331 cm³.

also, given,

→ the dimension of the base of the vessel are 15 * 12cm .

Let us assume that the rise in the level of water in the vessel is upto height h cm.

we know that,

  • Volume of cube = Volume of water rises .
  • volume of cuboid = Length × Breadth × Height

therefore,

→ 15 * 12 * h = 1331

→ 180h = 1331

→ h = (1331/180)

→ h = 7.39 (Ans.)

Hence, The rise in water level to height of 7.39 cm.

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