a cube of Edge 33 cm is melted and formed into a cylindrical wire of diameter 0.5 cm. what length of wire will be obtained from the cube?
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Concept Behind This Question Is All About Equality Of Volume, Which Is Given Below:-
Here, the cube is melted into a cylindrical wire, which means that their volumes are equal
So, length of edge of cube=33 cm
Diameter of the cylinder=0.5 cm
So, ATQ:-
πr²h=a³
22/7×(0.5/2)²×h=33³
11/56×h=35937
h=35937×56/11
h=182952
So, the length of the wire is 182952 cm, which is equal to 1829.52 m
Here, the cube is melted into a cylindrical wire, which means that their volumes are equal
So, length of edge of cube=33 cm
Diameter of the cylinder=0.5 cm
So, ATQ:-
πr²h=a³
22/7×(0.5/2)²×h=33³
11/56×h=35937
h=35937×56/11
h=182952
So, the length of the wire is 182952 cm, which is equal to 1829.52 m
yogesh3380:
what
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2
volume of cylindrical wire=volume of cube
volume of cube =side^3=33^3
volume of cylindrical wire =πr^2h=π(0.5/2)^2
So,
π(0.5/2)^2.length of wire=33^3
length of wire=182952cm=1.82952 km
volume of cube =side^3=33^3
volume of cylindrical wire =πr^2h=π(0.5/2)^2
So,
π(0.5/2)^2.length of wire=33^3
length of wire=182952cm=1.82952 km
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