Question

A cube of edge 9 cm is immersed completely in rectangular vessel containing water. If the dimensions of base are 15 cm ├Ч12 cm , find the rise in water level in vessel.

Answer 1

thanks again for your help and support

Answer 2

Answer:

We have,

$\sf{Edges\:of\:the\:given\:cube=9cm}$

$\sf{Volume\:of\:the\:cube=(9^3)\:cm^3\:=729\:cm^3}$

If the cube is immersed in the vessel, then the water level rises.

$\sf{Let\:the\:water\:rise\:level\:be\:x\:cm.}$

Clearly,

$\Rightarrow$ volume of the cube = Volume of the water displaced by it.

= Volume of the cube = Volume of a cuboid of dimensions 15 cm × 12 cm × x cm.

= 729 = 15×12×x

x = $\sf\frac{729}{15×12}cm$

x = $\cancel\dfrac{81}{20}cm$

•°• x = 4.05 cm.