Question

A cube of edge 9cm is immersed completely in rectangular vessel containing water. If the dimensions of base are 15 cm ×12m , find the rise in water level in vessel.

Answer 1

rise in water =volumeof cube/base of vessel=
9*9*9/15*12=
81/20=
4.05

Answer 2

hi friend,

Question:A cube of edge 9cm is immersed completely in rectangular vessel containing water. If the dimensions of base are 15 cm ×12m , find the rise in water level in vessel.


Answer:-

Given, edge of the cube = 9 cm

Dimension of the base of the rectangular vessel = 15 cm × 12 cm

Let the rise in water level in the rectangular vessel be h cm.

Since, the cube is completely immersed in the rectangular vessel,

∴ Volume of water displaced in the rectangular vessel = Volume of the cube

15 cm × 12 cm × h = (9 cm)3

15 cm × 12 cm × h = 729 cm3

h = (729/180) cm

⇒ h ≈ 4.05 cm

Thus, the rise in water level in the rectangular vessel is 4.05 cm approximately.



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