Question

A cube of external dimension 10 cm has an inner cubical portion of side 5 cm whose density is twice that of the outer portion. If this cube is just floating in a liquid of density 2 g/cm3, if the density of the inner portion is x gm/cc then fill the value of 9

Answer 1

The mass of the cube is 4.8 Kg.

Explanation:

Correct statement:

A cube of side 20 cm is floating on a liquid with 5 cm of the cube outside the liquid. If the density of liquid is 0.8 g / cm^3  then the mass of the cube is ?

Solution:

• The buoyant force is represented by Fba and is equal to the weight of the cube.
• Fb = mg
• Vi  x ρ(l) x g = mg
• m = ρl x Vi

Now put the values in the above formula:

m = [ 20 x 20 ] x 15 x 0.8

m = 60 x 0.8 g/cm^3

MAss "m" = 4.8 Kg

Thus the mass of the cube is 4.8 Kg.