A cube of ice floats partly in water and partly in kerosene oil
Answers
Let the volume of ice in water be a m³ and the volume of ice in K.oil be b m³
Therefore, Total Volume = a + b
Density of ice = density of water at 4° C × Specific Gravity.
∴ Density of the ice = 0.9 × 1000 kg/m³
Density of Ice = 900 kg/m³
Therefore, total mass of the ice cube = (a + b) × 900 kg
Theretofore, Its weight = (a + b) × 900 × 10
By the law of the Flotation, the total force of buoyancy by the water and the Kerosene oil will be equal to the weight of the ice cube.
∴ The total force of buoyancy = a × 1000 + Y × 800 kg
(a + b) × 900 = a × 1000 + b × 800
900a + 900b = 1000a + 800b
100a = 100b
∴ a = b
Hence, the ratio of there volume is 1 : 1.
Hope it helps .
#Dramqueen⭐
Because ice is the solid form of water so in water it floats upon it whereas in kerosene water do not mixes with it so it floats upon it.
_hope it helped_ plz mark it as brainliest