Physics, asked by Dark180Zeus, 7 months ago

A cube of iron (d=7.8 g/cm3)of length 5 cm floats in mercury (d=13.6 g/cm3).
What length of cube is submerged in the mercury.​

Answers

Answered by letmemakeyouwet
1

Explanation:

piron=7.8,pmercury=13.6

By Archimedes principle,

piron.(5×5×5).g=pmercury.(5×5×(5−x)).g+pwater(5×5×x)

7.8×53=13.6(53)−13.6×25×x+25x

x=1355×58=2.148

x=2.15∼x≈2.2㎝

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