Question

a cube of lead with edge 6 cm each is melted and form 27 equal cubes. what is length of edge of new cubes

Answer 1

Volume of large cube = 216
no. of small cubes =27
volume of a small cube =216÷27=8
${a}^{3} = 8 \\ a = 2$
edge length of small cube = 2cm

Answer 2

volume of first cube= volume of 27
hence volume of small cube =
$\frac{6 \times 6 \times 6}{27} \\ = 8$
now side
$= \sqrt[3]{8} \\ = 2$