Question

a cube of lead with edge measuring the 6 cm each is melted and formed into 27 equal cube. what will be the length of the edge of the new cube?

Answer 1

V of cube = A3
= 6×6×6=216

V of new cube=216÷27=8
so edge= cuberoot8=2

Answer 2

Answer:

$\huge\underbrace\purple{༒︎AnSwEr}$

Given,

Edge of orginal cube= 6cm

Volume of this cube=6^3=216 cm

Let, the edge of the new cubes be 'a' cm

27a^3=216

=> a^3=216/27

=>a^3=(6/3)^3

=>a=2 cm