Question

A cube of lead with edges measuring 6 and it is melted and formed into 27 equal cubes what will be the length of the edge of the new cubes

Answer 1

Volume of 1 lead cube = Vol. Of small 27 Cube

let the side be L Of big cube
l is the side of 27 Small cube.

vol. Of cube = L^3

L = 6m(edge of big cube)

l = lm(edge of formed small cube)

L^3=l^3 × 27cube

6^3 = 27 × l^3

216 = 27 × l^3
216/27 = l^3

8 = l^3

root cube of 8 = l

2 = l

so the edge of new cube will be 2m or cm.

Answer 2

lenght of the edge of the new cubes - 27/6 -4.5